The maximum numbers of possible interference maxima for slit separation equal to twice the wavelength in Young's double slit experiment, is
Text Solution
Verified by ExpertsThe correct answer is:
B
The condition of interference maxima is
Given, 
and 
The magnitude of 
lies between 0 and 1 .
When 
When 
When 
Thus, there is central maximum at 
, on either side of it maxima lie at 
and 
, so maximum number of possible interference maxima is five.
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